Unit 7 · Topic 09
Pendulums
Pendulum periods are approximations for small oscillations about equilibrium.
Unit 7PendulumsOpen navigation
Concept 01
Ideal point mass
Essential The minimum you should retain
For length L and small angle, T≈2πsqrt(L/g).
UnderstandInterpret and connect
The period is independent of mass and approximately independent of amplitude in that limit.
DeepenFormulation and conditions
The approximation uses sinθ≈θ.
ExploreConnections for further study
At larger amplitude the real period exceeds the simple approximation.
Worked example
Simple-pendulum period
An ideal L=1.00 m pendulum swings through a small angle; g=9.8 m/s².
- L=1.00 m
- g=9.8 m/s²
- small angle
Find T.
- Model
T≈2πsqrt(L/g).
- Substitution
T≈2πsqrt(1/9.8).
- Calculation
T≈2.007 s.
- Validity
The approximation requires small oscillations.
Mathematical relation
Pendulums
Approximate periods of simple and physical pendulums.
The simple formula is not exact at arbitrary amplitude.
DeepenVariables, conditions, and checks
Variables
- I_p
- moment of inertia about the pivot; usual unit: kg·m²
- d
- pivot-to-CM distance; usual unit: m
Conditions of application
- Small oscillations; sinθ≈θ.
Dimensional check
s.
The simple pendulum uses L; the physical pendulum requires I_p and distance d from pivot to center of mass.
Concept 02
A stated limit
Essential The minimum you should retain
The formula is not exact for arbitrary amplitudes.
UnderstandInterpret and connect
Small angles keep the angular restoring force nearly linear.
DeepenFormulation and conditions
Amplitude corrections appear when nonlinear terms in sinθ are retained.
ExploreConnections for further study
Stating amplitude or regime prevents extrapolation.
Concept 03
Rigid distribution
Essential The minimum you should retain
For small oscillations, T≈2πsqrt(I_p/(Mgd)).
UnderstandInterpret and connect
I_p is measured about the pivot and d joins pivot to center of mass.
DeepenFormulation and conditions
The body cannot automatically be replaced by a point mass at its CM.
ExploreConnections for further study
Moving the pivot changes both I_p and d.
Worked example
Rod as a physical pendulum
A uniform L=1.00 m rod pivots at one end; I_p=(1/3)ML² and d=L/2.
- L=1.00 m
- I_p=(1/3)ML²
- d=L/2
- g=9.8 m/s²
Find T.
- Model
T=2πsqrt(I_p/(Mgd)).
- Substitution
Insert I_p and d.
- Reduction
T=2πsqrt(2L/(3g)).
- Result
T≈1.64 s.
Concept 04
Simple as a limit
Essential The minimum you should retain
The simple pendulum concentrates all mass a distance L from the pivot.
UnderstandInterpret and connect
The physical pendulum retains the body's mass distribution.
DeepenFormulation and conditions
Both models share the small-oscillation limit.
ExploreConnections for further study
Choosing the correct model is part of the reasoning.
Concept review
Common errors
Each warning includes a concrete way to review the reasoning, not only an incorrect-answer marker.
Using T=2πsqrt(L/g) exactly at every amplitude.
It is a small-angle approximation.
Automatically treating a physical pendulum as a point mass.
Use the full body's I_p and distance d.